4+2x+2=x^2-2x+1

Solution for 4+2x+2=x^2-2x+1 equation:

4+2x+2=x^2-2x+1

We move all terms to the left:

4+2x+2-(x^2-2x+1)=0

We add all the numbers together, and all the variables

2x-(x^2-2x+1)+6=0

We get rid of parentheses

-x^2+2x+2x-1+6=0

We add all the numbers together, and all the variables

-1x^2+4x+5=0

a = -1; b = 4; c = +5;
Δ = b2-4ac
Δ = 42-4·(-1)·5
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-6}{2*-1}=\frac{-10}{-2}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+6}{2*-1}=\frac{2}{-2}
=-1
$